Question

How far apart two protons be if the electrostatic force exerted by one on another is equal to weight of electron?

Answer 1

Answer:The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron.

Explanation:

Mass of electron =$9.10\times 10^{-31} kg$

Weight of an electron= mg =$9.10\times 10^{-31} kg\times 9.8 m/s^2=8.918\times 10^{-30} N$

Charge on proton = $Q_1=Q_2=1.6\time 10^{-19} C$

Distance between two protons = r

$F_E=8.918\times 10^{-30} N$

$F_E=k\frac{Q_1\times Q_2}{r^2}$

$8.918\times 10^{-30} N=9\times 10^9 N m^2/C^2\times \frac{1.6\time 10^{-19} C\times 1.6\time 10^{-19} C}{r^2}$

$r=5.08 m$

The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron.

Answer 2

Answer:

5.005 m

Explanation:

K. q₁ . q₂ / r² = m . g

Here q₁ = q₂ = 1.6 x 10⁻¹⁹

∴ (9 x 10⁹) x (1.6 x 10⁻¹⁹) x (1.6 x 10⁻¹⁹) / r² = 9.1 x 10⁻³¹ x 10

∴ r² = 25.6

∴ r = √25.6

∴ r = 5.005 m