How far away from the surface of earth , the value of g becomes4℅ of the value on the surface of earth ?GivenR=6400km
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Answer:
Acceleration due to gravity g′=1004gs
Using g′=gs[R+hR]2
Or 1004gs=gs[R+hR]2
Or R+hR=102
⟹ h=4R=4×6400=25600 km
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Above is the answer thx for the points
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