How far from the surface of the earth does the acceleration due to gravity reduces by 51%
of its value at the surface of the Earth? (R=6400 km)
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Answer:
Given:
Radius of Earth = 6400 km
To find:
Height at which gravity reduces by 51%
Concept:
Let gravity at height h be g" , and gravity at Earth surface be g
So , g is reduced by 51%
Hence g" = 49% of (g)
Calculation:
Putting value of r = 6400 km
So final answer :
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2
#Physics11
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