How far is cord of length 8 cm from the centre of a circle of radius 5 cm
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Answer: AO =5 CM
AN =8CM
IN TRIANGLE ABC
(AO)^2=(AP)^2+(OP)^2
5^2=4^2. + OP^2. {AP= 1/2AB =4 CM }
25=16. +OP^2
OP^2 =25-16. =9
OP=3 cm
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Answered by
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Answer:
here ur answer
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hope it helps ☺☺
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