how far is is a a chord of length 8 cm from the centre of a circle of radius 5 cm
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It will be 3cm away from the centre.
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Answer:
3cm
Step-by-step explanation:
if the line from the center joing the chord is perpendicukar to the chord . Then it divides the chord into 2 equal parts
so, AC = BC
and 2AC = 8cm
AC = 4 cm
So ∆AOC forms a right angles triangle
therefore by Pythagores theorem
OC = 3cm
please refer the attachment for better understanding
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