Question

How far is the cliff from the sea level?

Answer 1

Answer:

Tan is the obvious way to go here, but just for variety you could use the Sine Rule too.

15sin50∘=dsin(180∘−90∘−50∘)

d=15×sin40∘sin50∘=12.58649447

h−15sin70∘=dsin(180∘−90∘−70∘)

h=12.58649447×sin70∘sin20∘+15=49.58110934

So The cliff is 49.58 feet high and 12.59 feet away.

Step-by-step explanation:

If d is the distance of cliff from the ship,

tan 70 = (h-15)/d and tan 50 =15/d

d = 15/ tan 50 = 12.59 ft.

h -15 = d tan 70 = 12.59 * 2.75 = 34.58 ft

h = 49 .6 ft

Answer 2

Answer:

mark me as brainliest

follow me

if my answer seems helpful