Question

How far is the point (-3,-7) from the line x=-2?

Answer 1

Answer:

1

Step-by-step explanation:

x=-2 can be written as 1x+0y+2=0

distance between a point(x1,y1) and a line(ax+by+c)=

$\frac{ | ax1 + by1 + c | }{ \sqrt{ {a}^{2} + {b}^{2} } }$

so the distance between (-3,-7) and x=-2 is

$\frac{ | - 3 \times 1 +( - 7 \times 0) + 2| }{ \sqrt{ {1}^{2} + {0}^{2} } }$

=

$1$

ALTERNATIVE WAY:

As x=-2 is parallel to y axis (-2,-7) is a point on this line and line joining (-3,-7) and (-2,-7) is perpendicular to x=-2

distance between x=-2 and (-3,-7) is -2-(-3)=1