Question

How FAR will a car travel if it accelerates from rest at 4 m/s/s for 10 seconds? *
Remember that d = 1/2 at^2, and that a is NOT the 10 m/s/s due to gravity here!

Answer 1

Answer:

200 m

Explanation:

As

S=Vi(Initial velocity)*t+1/2at²

We are given that the car starts from rest so we Simply put it 0.

We only multiply a=4m/s²& t= 10s with1/2.

Answer 2

Given :

• Initial velocity (u) = 0 m/s
• Acceleration (a) = 4 m/s²
• Time (t) = 10 seconds

To find :

• Distance (s)

According to the question,

In this question we will use Newton's third equation of motion,

→ s = ut + ½ at²

Where,

• s stands for Distance
• u stands for Initial velocity
• a stands for Acceleration
• t stands for Time

→ Substituting the values,

→ s = 0 × 10 + ½ × 4 × (10)²

→ s = 0 + ½ × 4 × 100

→ s = 0 + ½ × 400

→ s = 0 + 200

→ s = 200 m

.°. The distance is 200 m...

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More formula's :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as