How fast a man of 50kg run so that his kinetic energy be 625 joule
Answers
Answered by
136
K.E = 0.5mv²
v = sqrt(2K.E / m)
= sqrt(2 × 625 Joule / 50 kg)
= sqrt(625 Joule / 25 kg)
= 5 m/s
Velocity of man should be 5 m/s
v = sqrt(2K.E / m)
= sqrt(2 × 625 Joule / 50 kg)
= sqrt(625 Joule / 25 kg)
= 5 m/s
Velocity of man should be 5 m/s
Answered by
22
Answer:K.E=625J
M=50kg
K.E=1/2mv*2
625=1/2×50×v*2
625/25=v*2
By square root
25/5=v*2
5m/s=v
Explanation:
Similar questions
English,
7 months ago
Math,
7 months ago
Math,
7 months ago
Social Sciences,
1 year ago
Computer Science,
1 year ago