Question

How fast a man of 50kg run so that his kinetic energy be 625 joule

Answer 1

K.E = 0.5mv²

v = sqrt(2K.E / m)
= sqrt(2 × 625 Joule / 50 kg)
= sqrt(625 Joule / 25 kg)
= 5 m/s

Velocity of man should be 5 m/s

Answer 2

Answer:K.E=625J

M=50kg

K.E=1/2mv*2

625=1/2×50×v*2

625/25=v*2

By square root

25/5=v*2

5m/s=v

Explanation: