How fast is an electron moving if it has a wave number is equal to the square of distance it travels in one second?
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Here we are given that wavelength is equal to the distance travelled by the electron in 1 second, i.e. Place the values for h and m in the above equation that we have solved for v, i.e. Therefore, the electron is moving with a velocity of 0.027 m/s.
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= 0.027 m/s
The distance travelled in one second = velocity (v)
Given wavelength (λ) = velocity (v)
Therefore λ = h/mv becomes v = h/mv
⇒v2 = h/m
v=(√h/√m)
h is the Planck’s constant = 6.626 x 10-34 J s
m is the mass of the electron = 9.10939 x 10-31 kg
v = √6.626 x 10-34 J s/√9.10939 x 10-31 kg
= 0.027 m/s
The distance travelled in one second = velocity (v)
Given wavelength (λ) = velocity (v)
Therefore λ = h/mv becomes v = h/mv
⇒v2 = h/m
v=(√h/√m)
h is the Planck’s constant = 6.626 x 10-34 J s
m is the mass of the electron = 9.10939 x 10-31 kg
v = √6.626 x 10-34 J s/√9.10939 x 10-31 kg
= 0.027 m/s
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