Question

how fast must a meter stick be moving if its length is observed to shrink to 0.500m?​

Answer 1

Answer:

MARK AS BRAINLIEST

Explanation:

In order to observe a meter stick to shrink its length to 0.5 meters, it must move at a speed of 2.6×108ms 2.6 × 10 8 m s .

Answer 2

The idea of length contraction from special relativity is involved in this issue. The theory of relativity states that as an object moves in relation to an observer, its length varies. The following provides the length contraction formula: L' = L * sqrt(1 - v^2/c^2).

• In this problem, we are given that the observed length of the meter stick is 0.500m. We can assume that the rest length of the meter stick is 1m, since that is the standard length of a meter stick. Plugging in these values into the length contraction formula, we get: 0.500m = 1m * sqrt(1 - v^2/c^2)
• Simplifying and solving for v, we get:v^2/c^2 = 1 - (0.500m/1m)^2
• v^2/c^2 = 1 - 0.25
• v^2/c^2 = 0.75v/c = sqrt(0.75)
• v = sqrt(0.75) * cv ≈ 0.866 * c
• Hence, for the length of the metre stick to be observed to shrink to 0.500m, it must be moving at a rate of roughly 0.866 times the speed of light, or about 259,800 km/s.

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