Question

how fast should a man of 50 kg run so that his kinetic energy will be 625 joule​

Answer 1

Answer:

It is given that, mass of the man is 50 kg and kinetic energy is 625 joule.

So,

Kinetic Energy=1/2 mv²

: . 625=1/2×50×v²

: . 625=25v²

: . v²=625/25

: . v²=25

: . v=5 m/s

So man should run at a speed of 5 m/s

Answer 2

Answer:

0.05m/s

Explanation:

m = 50000 K.E. = 625J

K.E. = (1/2)mv^2

625 = (1/2) × 50000 × v^2

v^2 × 50000 = 625 ÷ 1/2

v^2 × 50000 = 625 × 2

v^2 × 50000 = 125

v^2 = 125/50000

v^2 = 0.0025

v = √0.0025

v = 0.05m/s

Therefore the man should run with a speed of 0.05m/s.