Question

How fast should a man of 50 kg run so that his kinetic energy be 625 j?
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Answer 1

Answer:

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Answer 2

Answer:

5m/s

Explanation:

KE =(1/2)mv^2

Given m =50kg

KE =625J

625 =(1/2)*50*v^2

v = sqrt(2*625/50)= 5m/s

Mans fast is 5m/s