Question

how fast should a man of 50 kg run so that is kinetic energy is 625 joule

Answer 1

H҈ e҈ y҈  f҈ r҈ i҈ e҈ n҈ d҈ 


$v {}^{2} = \frac{k.e \times 2}{m}$


$v {}^{2} = \frac{625 \times 2}{50}$


$v {}^{2} = 25$




$v = \sqrt{25} = 5meter \: per \: sec$



Hope it helps

Answer 2

since K.E. = 1/2 m v2.
all data are given....so v = 5m/s