Question

How fast should a man of 50kg run so that his kinetic energy be 625J?

Answer 1

Explanation:

K.E= I/2 MV2

625=I/2 X 50 X V2

625 = 25 X V2

625/25 = V2

25 = V2

root 25 = V

5m/s = V

Answer 2

Answer:5 ms-¹

Explanation:

m= 50kg

v=?

KE= 625J

We know,

KE= ½mv²

•°• 625=½×50(v)²

625= 25v². [°•° Cancelling 2 and

50 = 25]

25v²= 625

v²=625/25

v²= 25

v= √25

•°•,v= 5.