Question

how fast should a man of mass 60 kg Run so that his kinetic energy is 750 joules

Answer 1

EK(KINETIC ENERGY)=750J

M(MASS) =60kg

V(FINAL VELOCITY) = Root of 2EK/M

= Root of 2*750/60

=` Root of 1500/60=Root of 25

= 5m/s

Hope it helppzz..!!!

Answer 2

• Mass = 60 kg

• K.E = 750 J

• v = ?

→ K.E = (1/2)mv²

⇒ 750 = (1/2) × 60 × v²

⇒ v² = 150/6

⇒ v = √25

⇒ v = 5 m/s

∴  The man should run with a velocity of 5m/s