how fast should a man of mass 60 kg Run so that is kinetic energy is 750 Joule
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K.E = 1/2mv^2 = 750
1/2 (60)(v^2) = 750
30(v^2) = 750
v^2 = 25
v = 5 m/s
Therefore a man should run for 5 m/s to acquire an energy of 750 Joules
1/2 (60)(v^2) = 750
30(v^2) = 750
v^2 = 25
v = 5 m/s
Therefore a man should run for 5 m/s to acquire an energy of 750 Joules
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