Question

how fast should a man of mass 60 kg run so that is kinetic energy is 750 joule

Answer 1

H҈ e҈ y҈  f҈ r҈ i҈ e҈ n҈ d҈ 


$v {}^{2} = \frac{750 \times 2}{60}$


$v {}^{2} = 25 \\ \\ v = \sqrt{25} = 5 \: meter \: per \: sec$


Hope it helps you

Answer 2

Hey friend the answer is 1250 meters.
Hey friend pls mark it as the brainliest..