how fast should a man of Mass 60kg run so that his kinetic energy is 750J
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Answered by
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Ke = 1/2 mv^2
750 = 1/2 mv^2
v^2 = 25
v = 5 m / s
the speed 5 m / s
750 = 1/2 mv^2
v^2 = 25
v = 5 m / s
the speed 5 m / s
Answered by
0
Answer:
Ke = 1/2 mv^2
750 = 1/2 mv^2
v^2 = 25
v = 5 m / s
the speed 5 m / s
Explanation:
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