How fast should a man weighing 600N run so that his kinetic energy is 750J
Answers
Answered by
3
For, v = velocity, m = mass of man.
Kinetic Energy (KE) = 1/2 m v^2
So, v = (2 KE / m)^1/2
v = (2 . 750 / 60)^ 1/2
v = (25)^1/2 = 5 m/s
Kinetic Energy (KE) = 1/2 m v^2
So, v = (2 KE / m)^1/2
v = (2 . 750 / 60)^ 1/2
v = (25)^1/2 = 5 m/s
Similar questions