Question

How fast should girl of 35 kg run so that her kinetic energy becomes 700J?.

Answer 1

kinetic energy= 1/2mv^2,. 700= 1/2×35× v^2,. 1400/35=v^2, 40=v^2 , v= 2√10 , v= 6.32m/sec

Answer 2

Answer: SHE SHOULD RUN ‍♀️ AT 6.3 m/s

Explanation:

KE = 1/2mv^2

700  = 1/2*35*v^2

700*2/35 = v^2

1400/35 => 40 = v^2

root40 = v

=> v = 6.3 ( approx )