Question

How fast the reaction is at 25°C as compared to 0°C. If the activation energy is 65 KJ :-

Answer 1

Answer:

The rate of the reaction at 25°C will be 11.04 times the rate of the reaction at 0°C.

Explanation:

Rate of the reaction at 0° C temperature =$k_1$

$T_1= 0^oC=273 K$

Rate of the reaction at 25 °C temperature =$k_2$

$T_1=25^oC=298K$

$E_a=65kJ=65000 J$

$\log\frac{k_2}{k_1}=\frac{E_a}{2.303\times r}(\frac{T_2-T_1}{T_2T_1})$

$\log\frac{k_2}{k_1}=\frac{65000 kJ}{2.303\times 8.314J /K}\frac{298K-273K}{298 K\times 273 K}$

$\log \frac{k_2}{k_1}=1.043$

$k_2=11.04\times k_1$

The rate of the reaction at 25°C will be 11.04 times the rate of the reaction at 0°C.

Answer 2

Answer:

The reaction at 25°c is 11times faster than the reaction at 0°c if the activation energy is 65KJ.