Question

How FAST will a train be travelling if it accelerates from rest at 5 km/h/s for 14 s?

Answer 1

Given:-

• Initial velocity,u = 0m/s

• Acceleration ,a = 5km/h² = 5×18/5 = 18m/s²

• Time taken ,t = 14s

To Find:-

• Final velocity ,v

Solution:-

By using 1st equation of motion

• v = u+at

Substitute the value we get

→ v = 0 + 18×14

→ v = 252m/s

Therefore, the final velocity of train will be 252 m/s.

Additional Information !!

Some equation of motion are

• v = u +at

• s = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

Answer:

Given :-

• A train was travelling of its accelerats from rest at 5 km/h for 14 secs.

To Find :-

• What is its final velocity.

Formula Used :-

First equation of motion,

$\boxed{\bold{\large{v\: =\: u\: +\: at}}}$

Solution :-

Given :-

• Initial velocity (u) = 0 m/s
• Acceleration (a) = 5 km/h = 5 × $\dfrac{18}{5}$ = 18 m/s²
• Time (t) = 14 secs

According to the question by using the formula we get,

⇒ v = 0 + (18)(14)

⇒ v = 0 + 252

➠ v = 252 m/s

$\therefore$ The final velocity of the train is 252 m/s .

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