Question

how gear system use in obtaining gain in speed and gain in torque​

Answer 1

Answer:

The gear ratio, or velocity ratio, between a pair of gear wheels is in inverse ratio to the number of teeth on each. Thus:

 

 NB/NA = DA/DB= nA/nB

NB = NA (nA/nB)

Where:

NA= rev per min of gear A, nA =  number of teeth on A

NB = rev per min of gear B, nB =  number of teeth on B

DA = Diameter of gear A

DB = Diameter of gear B  

Example : Load gear compartment!

Power, Speed and Torque:

The power transmitted by a shaft is directly proportional to the speed of revolution and the torque acting on it

 

 Power [kW] = 2 p N T / (60 x 1000) [N.m/s]

Then

 TA NA = TB NB

 

For a given power, therefore, the torque is inversely proportional to the speed of revolution and if the re min is reduced the torque will be increased in the same ratio (assuming 100% gear efficiency).

 

 TB/TA = nB/nA

Where:

 TA = torque transmitted by A

 TB = torque transmitted by B

Velocity or gear ratio (ig) = number of teeth on driven gear/number of teeth on driver gear.

 

TB = TA (nB/nA) = TA/ ig

hope you like it

please mark it as the brainliest answer...