how gravitational force is equal to 9.8
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Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is9.8 m/s2. When discussing theacceleration of gravity, it was mentioned that the value of g is dependent upon location
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g = MG/R^2,
where g – Acceleration due to gravity
M – mass of the Earth = 5.98 x 10^24 kg
G – Universal gravitational constant = 6.673 x 10^-11 Nm^2kg^-2
R – Radius of the Earth = 6.38 x 10^6 m
g = (5.98 x 10^24 x 6.673 x 10^-11) / (6.38 x 10^6)²
g = (39.90454 x 10^13) / (40.7044 x 10^12)
g = 0.98034954 x 10
g = 9.8 m/s²
Note:
Unit of g = (kg x N x m² x kg ^-2)/ m^2
Unit of g = N x kg^-1
Unit of g = kg x m x s^-2 x kg^-1, where N = kg x m x s^-2
Unit of g = ms^-2 OR m/s²
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