How high is the ledge from the ground
Answers
Answer:
t = 0.5 sec
a = 10m/s^2 (gravitational force)
u = 0 m/s
i. Using first law of motion
v = u+at
v = 0+10*0.5
v = 5 m/s
ii. Average speed = distance travelled/time
Using second law of motion to compute distance travelled
s = ut+1/2*a*t^2
s = 1/2*10*0.5*0.5
s = 1.25 m
Hence average speed = 1.25/0.5 = 2.5 m/s
iii. Height of the ledge would be equal to the distance travelled
And hence, height of the ledge = 1.25m.
Answered by | 26th Jun, 2013, 04:22: AM
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