how high up is a 3.00 kg object that has 300 J of energy?
Answers
Answer:
The height of the object is 10.204 meters.
Explanation:
In our case, we are dealing with gravitational potential energy. To solve this, we will use the formula:
GPE = mgh
where
GPE is the gravitational potential energy, unit is in Newton-meter (N.m) or
Joules (J)
m is the mass of the object, unit is in kg
g is the acceleration due to gravity, equivalent to 9.8 m/
h is the height of the object, unit is in meters (m)
For the given information
m = 3.00 kg
GPE = 300 J
h = ?
Solving the problem
Let us use the formula for gravitational potential energy, we have:
GPE = mgh
Then substitute the given information, we have:
300 J = (3 kg)(9.8 m/)h
Dividing both sides of the equation by (3 kg)(9.8 m/), we have:
h = 10.204 meters
Therefore, the height of the object is 10.204 meters.
To learn more about gravitational potential energy, just click the following links:
Definition of Potential energy
brainly.ph/question/233160
Example of potential energy
brainly.ph/question/78768
Additional example problem with solution
brainly.ph/question/2654296
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Answer:
The object is at a height of 10.2 m.
Explanation:
- Potential Energy: The energy possessed by an object due to its shape, configuration and position is called potential energy. The SI unit of potential energy is Joule(J).
- The formula for potential energy, P.E = mgh
Where m = mass of the object. h = height of the object
g = acceleration due to gravity = 9.8 m/s²
- Given data: m = 3 kg, P.E. = 300 J, g = 9.8 m/s²
Here we have to find 'h'.
Putting all the values in above formula, 300 = 3 × 9.8 × h
h = = 10.2 m
∴ The object is at a height of 10.2 m.
To know more about potential energy visit the link below:
https://brainly.in/question/9929810
https://brainly.in/question/8836701