Question

How high would you have to lift a 1000 kg car to give it a potential energy of:(a) 2.0 x 103 J, (b) 2.00 x 105 J.​

Answer 1

$P.E = mgh \\ h = \frac{P.E}{mg}$

a)

$h = \frac{2 \times {10}^{3} }{1000 \times 10} \\ h = 0.2m$

b)

$h = \frac{2 \times {10}^{5} }{1000 \times 10} \\ h = 20m$

Answer 2

Answer:

The object should be lifted by 0.2m and 20.4m to gain the potential energy of $2.0 \times 10^3 J$ and $2.0 \times 10^5 J$ respectively.

Explanation:

Potential energy:

• Potential energy is the energy stored in a body that depends on the given position with a reference position.
• When a body is lifted to a certain height h, then the potential energy is given by virtue of its height.
• Work done in lifting the object is stored as potential energy, and is given the product of force and height i.e.,

       $U=mgh$

Given mass of the car, m = 1000 kg

Let us take acceleration due to gravity, $g=9.8m/s^{2}$

a) Given the potential energy, $U=2.0 \times 10^3 J$

Using the formula of potential energy,

$U=mgh\implies 2.0 \times 10^3=1000\times 9.8\times h$

$\implies h= \dfrac{2.0 \times 10^3}{1000\times 9.8}$

          $=\dfrac{2}{9.8} \approx0.2m$

Therefore, the object should be lifted by 0.2m to gain the potential energy of $2.0 \times 10^3 J$

b) Given the potential energy, $U=2.00 \times 10^5 J$

Using the formula of potential energy,

$U=mgh\implies 2 \times 10^5=1000\times 9.8\times h$

$\implies h= \dfrac{2 \times 10^5}{1000\times 9.8}$

          $=\dfrac{200}{9.8} \approx20.4m$

Therefore, the object should be lifted by 20.4m to gain the potential energy of $2.0 \times 10^5 J$

For more info:

https://brainly.in/question/8836701

https://brainly.in/question/25632385