Question

how in rhombus AB is parallel to CD and bc is parallel to ad​

Answer 1

Answer:

Step-by-step explanation:

ABCD is a rhombus.        

∴ AB = BC = CD = AD        

Also, AB || CD an AD || BC        

Now, AD = CD ⇒∠1 = ∠2 ...(1)

[Angles opposite to equal sides-are equal]        

[Opposite sides of the parallelogram]

Also, CD II AB

∴ ∠1 = ∠3        

and AC is AC is transversal.    

∴ ∠1 = ∠3        

⇒ From (1) and (2), we have                            

 ∠2 = ∠3 and ∠1 = ∠4      

⇒AC bisects ∠C as well as ∠A.        

Similarly, we prove that BD bisects ∠B as well as ∠D