How is √ [2A² (1 + cosθ)] = √ [4A² cos² θ/2] ?
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Solution :
By applying the identity of the half angle identity.
cos^2( θ/2 )= 1 + cosθ / 2
=> 1 + cosθ = 2cos^2( θ/2 )
By putting the value of (1 + cosθ) in √ [2A² (1 + cosθ)]
Here, the value of (1 + cosθ) is 2cos^2( θ/2 ).
Now, put this 2cos^2( θ/2 ) in the place of (1 + cosθ)
=> √ [2A² (1 + cosθ)] = √ [4A² (cos² θ/2)]
=> √ [2A² (1 + cosθ)] = √ [4A² cos² θ/2]
.°. √ [2A² (1 + cosθ)] = √ [4A² cos² θ/2]
Hence, it is proved.
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