Chemistry, asked by sharmilidas1, 3 months ago

how is a bronsted lowry base distinguished from an Arrhenius base? explain with example​

Answers

Answered by umamahesh2237
0

An Arrhenius base is a molecule that when dissolved in water will break down to yield an OH- or hydroxide in solution. To recognize the Arrhenius base look for a molecule ending in OH, but not following CHx which refers to an alcohol.

Arrhenius base examples include:

Sodium hydroxide – NaOH

Potassium hydroxide – KOH

Magnesium hydroxide – Mg(OH)2

and so many more…

This is where we start to see the difference between the Bronsted-Lowry and Arrhenius definitions. While the Arrhenius base referred specifically to the hydroxide (OH-) ion, the Bronsted-Lowry base refers to any atom or ion capable of accepting or bonding to a free proton in solution.

Referring back to the HNO3 + NH3 reaction above, when ammonia picks up the free H+ it acts as a proton-acceptor. NH3 is the Bronsted-Lowry base in this example.

Additional examples include:

Methanol – CH3OH

Formaldehyde – H2CO

And even water – H2O

Hope it helps you.

Namaste.

Answered by dakshveer123456789
0

Answer:

Bronsted Concept of Acids and Bases

An Arrhenius Acid is something that donates a proton to water, and Bronsted-Lowry Concept extends this to any substance, where an acid is a proton donor and a base is a proton acceptor

Ammonia is the Bronsted-Lowry base because it is the 'proton acceptor' - it accepts a hydrogen atom from water. On the other hand, water is the Bronsted-Lowry acid because it is the 'proton donor'.

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