How is conservation of internal energy expressed for system during an isovolumetric process. a) Q=W=0 , So DU=0 Ui=Uf b) Q=0 , So DU=-W c) DT=0 ,So DU=0, therefore, DU= Q-W=0 or Q=W d) DV=0 ,So PDV=0 and W=0, therefore, DU=Q
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The answer for this question is option D) ΔV=0, so PΔV=0 and W=0, therefore, ΔU=Q
Explanation:
The isovolumetric or more preferably the isochoric process is the process where the volume remains unchanged or constant that is it does not change for the given values of pressure and temperature. Therefore in this following process, the ΔV is zero. Therefore as we know that:
W = PΔV hence when ΔV = 0 then W also becomes zero.
Therefore from the first thermodynamic equation which is,
ΔU = Q + W, becomes ΔU = Q, as W = 0.
Hence this matches with option D hence option D is correct.
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