how is distance =h+h=2h
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1
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At a distance 2h m from the foot of a tower of height h m, the top of the tower and a pole at the top of the tower subtend equal angles. Height of the pole should be
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Answered by
1
Answer:
In ΔABD, tanα= 2h/ h ⇒tanα= 2 1 In ΔABC,tan2α= 2hh+p⇒1−tan 2 a 2tanα = 2h h+p 1) 2 2( 2 1 = 2h h+p⇒
3
4
=
2h
h+p
⇒8h=3h+3p
⇒5h=3p⇒p=
3
5h
m
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