how is electric field intensity at a point related to the potential gradient there
Answers
Answered by
0
Explanation:
E=-dV/dr...............
Answered by
2
Heyaa buddy !!!
Here's your answer....
The electric field at a point can be defined as the negative of potential gradient.
Here, the negative sign implies that measuring from tye positive plate the potential drops with increasing distance.
Hope this will help yaa....
Mark as brainliest if this helped you....
:)
Attachments:
Similar questions