Question

how is electrolysis of water done? explain with the help of a labelled diagram. what are the productc of electrolysis of water ​

Answer 1

Hey mate!

I am here with your answer,

Electrolysis of water is the decomposition of water into oxygen and hydrogen gas due to the passage of an electric current. The reaction has a standard potential of −1.23 V, meaning it ideally requires a potential difference of 1.23 volts to split water.

The Electrolysis of Water. Water can be decomposed by passing an electric current through it. When this happens, the electrons from the electric current cause an oxidation-reduction reaction. At one electrode, called the cathode, electrons pass into the solution and cause a reduction.

In a polymer electrolyte membrane (PEM) electrolyzer, the electrolyte is a solid specialty plastic material. Water reacts at the anode to form oxygen and positively charged hydrogen ions (protons). The electrons flow through an external circuit and the hydrogen ions selectively move across the PEM to the cathode.

Hope this will help you

Answer 2

$\huge \bold{ELECTROLYSIS}$

Electrolysis is the chemical decomposition of a compound when electricity is passes through the aqueous solution of that compound.

$\huge \bold{WATER}$

Water is a non polar covalent compound , which means electrons are equally distributed between hydrogen and oxygen atoms.

$\huge \bold{ELECTROLYSIS \: OF \: WATER}$

Since, water is a non polar covalent compound so its don't conduct electricity and don't dissociate so, during electrolysis of water sulphuric acid is used to enchance the conductivity of water and to form ions.

ELECTROLYTE :---

$H_2O \longrightarrow H^{+} + OH^{-1}$

$H_2SO_4 \longrightarrow 2H^{+} + SO_4^{-2}$

When electricity is passed through the solution with inert electrodes.

$\bold{AT \: CATHODE}$

$H^{+}$ migrates towards cathode and except electrons to be neutral.

$H^{+} + 1e^{-} \longrightarrow H \times 4$

$2H + 2H \longrightarrow 2H_2$

So a colourless odorless gas hydrogen evolves from Cathode which burns with pop sound and blue flame.

$\bold{AT \: ANODE}$

$OH^{1-} \: and \: SO_4^{-2}$ migrates towards cathode but hydroxl ion lies below sulphate radical hence discharges and loses electrons to be neutral.

$OH^{1-} - 1e^{-} \longrightarrow OH \times 4$

$4OH \longrightarrow 2H_2O + O_2$

So, a colourless odorless gas evolves from anode, which rekindles glowing splinter.