Physics, asked by mbakshi37, 8 months ago

How is Escape Velocity from Earths Surface Arrived At ? How Much is Escape of a Rocket weihning 1.8 tonnes at SriHariKota ?​

Answers

Answered by Everythingpurple
3

Pardon me but i think you are mistaken:

Rockets do not need to reach escape velocity to leave the Earth's orbit. They can escape at an arbitrarily small velocity, as long as they have sufficient potential (chemical fuel) energy to sustain the process.

Only projectiles need to leave the Earth's surface at the escape velocity!

First off, a rocket launched at that speed from the surface would disintegrate if not BURN up in the atmosphere long before reaching space - but in practice the segment where an interplanetary rocket accelerates is short enough comparing to its total trajectory.

A rocket, continuously accelerated by its exhaust, need not reach ballistic escape velocity at any distance since it is supplied with additional kinetic energy. It can achieve escape at any speed, given a suitable mode of propulsion and sufficient propellant to provide the accelerating force on the object to escape.

The escape velocity is nice as a "milestone", a marker to compare requirements and actual velocities against, and to train/play/learn with simulated, idealized models, but it never applies directly - it's just an arbitrary, if evocative data point to compare actual velocities to.

To answer your questions in short;

Currently we have no means to protect objects in space, we can only use propulsion. Modern rockets use Hydrogen and Oxygen in a combustion engine to release exhaust gases and launch the vehicle. Although, the use of additional Ramjets or Scaemjets is being considered, which use atmospheric oxygen, instead of oxygen tanks.

The escape velocity is 11.2 km/s at the surface, no rocket weighing 1.8 tonnes at sriharikota can survive that.

However, I provided attachments of velocity-altitude graphs, showing the ideal velocities for a rocket at different altitudes.

Graph 1 is from my favourite game kerbal space program! it shows the optimal velocity at different altitudes!(X=altitude, Y=velocity)(not to scale)

Graph 2 is the actaul flight path of the Saturn 5 Rocket from the Apollo 11 Mission!! (from NASA official source)

Pardon me if i was wrong.

Hope it helps!!

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Answered by HolyGirl
44

A teaspoonful of neutron star would weigh 6 billion tons:

A neutron star is the remnants of a massive star that has run out of fuel. The dying star explodes in a supernova while its core collapses in on itself due to gravity, forming a super-dense neutron star. Astronomers measure the mind-bogglingly large masses of stars or galaxies in solar masses, with one solar mass equal to the Sun’s mass (that is, 2 x 1030 kilograms/4.4 x 1030 pounds). Typical neutron stars have a mass of up to three solar masses, which is crammed into a sphere with a radius of approximately ten kilometres (6.2 miles) – resulting in some of the densest matter in the known universe.

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