Question

How is it possible?Only valid answers are accepted

Let a = b

Then,we can write as:
$a \times b = {a}^{2}$

Now,adding (-b^2) both sides

$ab - {b}^{2} = {a}^{2} - {b}^{2}$

$b(a - b) = (a + b)(a - b)$

[Using identity a^2 - b^2 = (a+b)( a-b) and on the R.H.S taking b as common]
$b = \frac{(a + b)(a - b)}{(a - b)}$
$b = a + b$
b = b+b

[Because a = b]

2b = b

Now,put any number in value of b, suppose we put 1,then:

2×1 = 1
2=1

​​

Answer 1

Answer:

Which of the following are greater than 0.85?

Choose 2 answers:

a) 1.3

b) 8 tenths

c) 9/10

pls answer it fast

Answer 2

Answer:

Let a = b

Then,we can write as:

$a \times b = {a}^{2}$

Now,adding (-b^2) both sides

$ab - {b}^{2} = {a}^{2} - {b}^{2}$

$b(a - b) = (a + b)(a - b)$

[Using identity a^2 - b^2 = (a+b)( a-b) and on the R.H.S taking b as common]

$b = \frac{(a + b)(a - b)}{(a - b)}$

$b = a + b$

b = b+b

[Because a = b]

2b = b

Now,put any number in value of b, suppose we put 1,then:

2×1 = 1

2=1

hope it is helpful thank you have a nice day