How is it possible to have half water molecule in a molecule of plaster of paris?
Answers
Explanation:
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Plaster of Paris is calcium sulphate hemihydrate . The formula for Plaster of Paris is CaSO₄. \frac{1}{2}
2
1
H₂O.
Plaster of Paris is prepared from Gypsum. Gypsum is calcium sulphate dihydrate [ CaSO₄. 2 H₂O ]
Plaster of Paris is prepared by heating Gypsum to a temperature of 100°C in a kiln.
When gypsum is heated , it loses three fourth of its water of crystallization and forms plaster of Paris .
CaSO₄. 2 H₂O ----------------> CaSO₄. \frac{1}{2}
2
1
H₂O+ 1 \frac{1}{2}
2
1
H₂O
It is not possible to have half molecule of water. The formula CaSO₄.1/2 H₂O means that two formula units of CaSO₄ shares one molecule of water , in such a way that the effective water of crystallisation of one particular unit of calcium sulphate comes to 1/2 molecule of water.
Plaster of Paris = 2CaSO₄.H₂O , OR , CaSO₄.1/2 H₂O
Answer:
Explanation:
it is possible because 2 molecules of plaster of paris together shares one molecule of water . so 1 molecule of plaster of paris share half molecule of water.
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