Question

how is relative density of a solid determined by using Archimedes' principle? derived the formula used​

Answer 1

Explanation:

Archimedes’ Principle or the physical law of buoyancy was discovered by the ancient Greek mathematician and inventor Archimedes. It states that any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant, force the magnitude of which is equal to the weight of the fluid displaced by the body. The volume of displaced fluid is equivalent to the volume of an object fully immersed in a fluid.

To determine relative density of a substance using Archimedes principle take a vessel and put some amount of water and mark the level of water then, fully immersede the object and then mark its level.Now find the difference between both marked values.Now measure the mass on a scale.And according to the following formula find the density.

Density = Mass/Volume

For Example : Your object creates a difference of 10 ml in your container when submerged.And, it weighs 20 grams.Then,

D= 20/10 g/cc

= 2 g/cc

Now, that you have found the volume you can easily find the relative density.

Relative density = Density of substance/Density of water

Density of water = 1 g/cc

Relative Density = 2

I HOPE IT HELPS.

Answer 2

Archimedes principle states that the Buoyancy force on the solid object is equal to the weight of the water displaced.

Explanation:

• Archimedes principle states that the buoyancy force on the solid object is equal to the weight of the water displaced.
• As the density of water is 1 g / cm^3, this provides the way to determined the volume of an irregular shaped object.
• As we know that
• Mass of object - apparent weight when submerged = Density of water x volume of object