Question

how is sinA related with cosA

Answer 1

$\displaystyle \sin^2 A + \cos ^2 A = 1\\\\\sin^2A = 1-\cos^2 A\\\\\therefore \sin A = \sqrt{1- \cos^2 A}$

Answer 2

Answer:

sin- cos =1

cos - 1 = sin

1 - tan= cos

1. sin (90- tita) = cos tita

2. Cos (90-tita) = tan tita