how is the emf if a cell related to the electrode potential
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Hi there ,
《 E 》Electrode potential is the electromotive force between two electrodes , its calculated by forming a galvanic cell between element electrode with hydrogen electrode
● The emf =
E cell = E cathode - E anode
☆ As example
If u know E cu is +0.34 v = cathode
E zn is - 0.76 v = anode
So, Ecell = 0.34 -(-0.76) = 1.1 v
♡ Hope the answer is helpful
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vipinkumar082002:
thanks bhai
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