How is the following conversion carried out? Ethyl magnesium chloride → Propan-1-ol.
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by nickel it is magnesium chloride propanol to
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The reaction will go like
H – C – H = O + C2H5 -> Mgcl -> C2H5 – CH2 – O-Mg+cl –in the presence of H2O-> Mg(OH)cl +C3H7 – OH (Propan – 1 – ol)
When the methanol and ethyl magnesium are treated together then the adduct substance will be produced. Here that substance is treated in the presence of H2O will give out Proan – 1 – ol.
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