Question

How is the following conversion carried out? Methyl magnesium bromide → 2-Methylpropan-2-ol.

Answer 1

The reaction will go like

H3C – C – (H3C)  = O + CH3 -> MgBr -> CH3 – C – (CH3) – (CH3) – O-Mg+Br –in the presence of H2O-> Mg(OH)Br +CH3 – C – CH3 – CH3 – OH (2 – Methylpropan2 – 2 - ol)

When the propane and methyl magnesium bromide are treated together then the adduct substance will be produced.

Here that substance is treated in the presence of H2O will give out 2-methylpropane – 2 - ol.