Science, asked by pitalesarika, 5 hours ago

how is the frequency of a tuning fork decided

Answers

Answered by dttashap28
1

Answer:

The frequency of a tuning fork depends on its dimensions and what it's made from:[7]

{\displaystyle f={\frac {1.875^{2}}{2\pi l^{2}}}{\sqrt {\frac {EI}{\rho A}}}}{\displaystyle f={\frac {1.875^{2}}{2\pi l^{2}}}{\sqrt {\frac {EI}{\rho A}}}}

where:

f is the frequency the fork vibrates at in hertz.

1.875 is the smallest positive solution of cos(x)cosh(x) = −1.[8]

l is the length of the prongs in metres.

E is the Young's modulus (elastic modulus or stiffness) of the material the fork is made from in pascals.

I is the second moment of area of the cross-section in metres to the fourth power.

ρ is the density of the material the fork is made from in kilograms per cubic metre.

A is the cross-sectional area of the prongs (tines) in square metres.

The ratio

I

/

A

in the equation above can be rewritten as

r2

/

4

if the prongs are cylindrical with radius r, and

a2

/

12

if the prongs have rectangular cross-section of width a along the direction of motion.

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