Question

How is the law of coservation of matter verified in the experiment of calcium chloride and sodium sulphate?

Answer 1

Law of conservation of mass: This law states that the total mass in a chemical reaction remains constant that is the total mass on the reactant side will be equal to the total mass on the product side in a chemical reaction.

Now, in a chemical reaction:

CaCl_2(s)+Na_2SO_4(aq.)\rightarrow 2NaCl(aq.)+CaSO_4(aq.)CaCl2​(s)+Na2​SO4​(aq.)→2NaCl(aq.)+CaSO4​(aq.)

\text{Mass on reactant side}=\text{Mass of }CaCl_2+\text{Mass of }Na_2SO_4Mass on reactant side=Mass of CaCl2​+Mass of Na2​SO4​

\text{Mass of }CaCl_2=40+(2\times 35.5)=111amuMass of CaCl2​=40+(2×35.5)=111amu

\text{Mass of }Na_2SO_4=(2\times 23)+32+(4\times 16)=142amuMass of Na2​SO4​=(2×23)+32+(4×16)=142amu

Mass of the reactant = 253 amu.

\text{Mass on product side}=\text{Mass of }2NaCl+\text{Mass of }CaSO_4Mass on product side=Mass of 2NaCl+Mass of CaSO4​

\text{Mass of }2NaCl=2\times(23+35.5)=117amuMass of 2NaCl=2×(23+35.5)=117amu

\text{Mass of }CaSO_4=40+32+(4\times 16)=136amuMass of CaSO4​=40+32+(4×16)=136amu

Mass of the product = 235 amu.

As ,the mass of reactant = Mass of product

Hence, this experiment verifies the law of conservation of mass.