How is the magnetic field inside a current carrying solenoid used to make an electromagnet? Explain with the help of diagram. List two factors on which the strength of magnetic field produced by a current carrying solenoid depends.
Answers
B=u°ni where n is no. of turns per unti length agar solenoid ke ander metal daal denge toh magnetic ke karan induced current se usmain bhi magnetic property aa jayegi vo bhi magnetise ho jayega agar hum metal main soft iron dalte hai toh yeh ek temporary magnet ki tarah behave karega and steel ek permanet magnet ki tarah
Answer:
Step-by-step explanation:
Electromagnet is the device which produce magnetic field when current is passing through the coil. In solenoid, coil is wrapped with many numbers of turn, when current is passes through the coil, it produce magnetic field along the axis of the solenoid. Hence it is used as the electromagnet.
Magnetic field duw to current carrying solenoid is given by:B = μ0nIwhere n is the no.of turns per unit length.I is the current through the solenoid.Therefore magnetic field depends of these two factors.where μ0 is the permeabilit which is constant