Question

how is the ratio of 64cm^2 and 121cm^2 is 8/11?​

Answer 1

Answer:

Given: the area of the two triangles is 121 cm2 and 64 cm2 respectively and the median of the first triangle is 12.1 cm Required to find: the corresponding median of the other triangle We know that, The ratio of the areas of the two similar triangles are equal to the ratio of the squares of their medians. ar(triangle1)/ ar(triangle2) = (median of triangle 1/median of triangle 2)2 121/ 64 = (12.1/ median of triangle 2)2 Taking the square roots on both LHS and RHS, we have 11/8 = (12.1/ median of triangle2) = (12.1×8)11(12.1×8)11 Therefore, Median of the other triangle = 8.8 cm. on the-areas-two-similar-triangles-are-121-and-respectively-the-median-the-first-triangle-12