Question

how is the resolving power (rp )of a microscope affected when the (a) wave length of illumination radiation decreases and (b) diameter of the object lens decreases ? state reasons to justify your answer​

Answer 1

Answer:

HOPE IT WILL HELP YOU........

PLEASE MARK IT AS BRAINLIEST...........

Explanation:

resolving power = 1/ dmin = 2 U sin(beta)/ 1.22 (lamda)

(i) Where lamda is a wavelength. So, if wavelength of illuminating radiation is decreased then resolving power increases.

(ii) On decreasing diameter , beta decreases so resolving power as well decreases.