how is the second step come up
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Anonymous:
because nCr = nC(n-r) that 8c5 = 8c(8-5) = 8c3
thanks a lot
how to expand 8c3
nCr = n! divided by (n - r)! * r! that is 8C3 = 8!/(8-3)!(3)!
8! = 8*7*6*5*4*3*2*1 similarly 3! = 3 * 2 * 1
means... 8×7×6×5×4×3×2×1 / (5×4×3×2×1)(3×2×1)
thanks..
yes!
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forget second step just solve the first one directly with the formulae
nCr = n! / (n-r)! r!
nCr = n! / (n-r)! r!
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