how is the value of slope of kmax of photo electron-frequency of photon graph equal to plancks constant
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Answer:
Explanation:
Correct option is
D
charge of electron
hv=hv
0
+ev
0
v
0
=
e
h
v−
e
h
v
0
On comparing this equation with the straight line equation, i.e y=mx+c
The slope of v
0
vs v is (v
0
is stopping potential)
(slope)
1
=
e
h
or K
max
=hv−hv
0
Thus, slope of K
max
vs v is
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